x^2+10^2=x+4^2

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Solution for x^2+10^2=x+4^2 equation: 



x^2+10^2=x+4^2

We move all terms to the left:

x^2+10^2-(x+4^2)=0

We add all the numbers together, and all the variables

x^2-(x+4^2)+100=0

We get rid of parentheses

x^2-x+100-4^2=0

We add all the numbers together, and all the variables

x^2-1x+84=0

a = 1; b = -1; c = +84;
Δ = b2-4ac
Δ = -12-4·1·84
Δ = -335
Delta is less than zero, so there is no solution for the equation

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